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-14x^2-46x-12=0
a = -14; b = -46; c = -12;
Δ = b2-4ac
Δ = -462-4·(-14)·(-12)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-38}{2*-14}=\frac{8}{-28} =-2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+38}{2*-14}=\frac{84}{-28} =-3 $
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